How high is my ceiling?

Algebra Level 3

0.00001 + n = 0 2 n = ? \left \lceil 0.00001 + \sum_{n=0}^{\infty} 2^{-n} \right \rceil = \, ?

Notation : \lceil \cdot \rceil denotes the ceiling function .


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1 solution

Geoff Pilling
May 15, 2016

0.00001 + n = 0 2 n = 2.00001 0.00001 + \sum_{n=0}^{\infty} 2^{-n} = 2.00001 .

So 0.00001 + n = 0 2 n = 3 \left \lceil 0.00001 + \sum_{n=0}^{\infty} 2^{-n} \right \rceil\ = \boxed3

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