Which Pythagorean?

Geometry Level 1

sin θ = 3 8 \sin\theta =\dfrac 38

If tan 2 θ = m n , \tan^2\theta=\frac { m }{ n }, where m m and n n are coprime positive integers, find m n . mn.


The answer is 495.

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2 solutions

Kay Xspre
Mar 13, 2016

tan 2 ( x ) = sin 2 ( x ) 1 sin 2 ( x ) = 9 64 1 9 64 = 9 55 m n = 495 \tan^2(x) = \frac{\sin^2(x)}{1-\sin^2(x)} = \frac{\frac{9}{64}}{1-\frac{9}{64}} = \frac{9}{55}\Rightarrow mn = 495

is this a formula you used? if yes, then what part of the 8 fundamental identities is this?

Louis Jayson Santos - 3 years, 4 months ago
Susanna Kraeski
Mar 29, 2021

If sin θ = 3 8 \sin \theta = \frac{3}{8} , then by Pythagorean theorem tan θ = 3 55 \tan \theta = \frac{3}{\sqrt{55}} tan 2 θ = 9 55 \tan^2 \theta = \frac{9}{55} m n = 495 \ mn = 495

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