How is this supposed to work?

Algebra Level 3

Evaluate this expression without using a calculator. ( 230495720348 1230487109384 + 2 ) ( 1230487109384 230495720348 + 1 ) ( 1 + 230495720348 1230487109384 ) ( 1 + 1230487109384 230495720348 1 ) . (230495720348-1230487109384+2)(1230487109384-230495720348+1)-(1+230495720348-1230487109384)(1+1230487109384-230495720348-1).


The answer is 2.

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3 solutions

The Adammz
Aug 31, 2015

Let:

a = 230495720348 a=230495720348

b = 1230487109384 b=1230487109384

( a b + 1 ) ( b a + 1 ) ( 1 + a b ) ( 1 + b a 1 ) (a-b+1)(b-a+1)-(1+a-b)(1+b-a-1)

( a b + 1 ) ( b a + 1 ) ( 1 + a b ) ( b a ) (a-b+1)(b-a+1)-(1+a-b)(b-a)

Expand them and we get:

2 a b a 2 b 2 a + b + 2 ( 2 a b a 2 b 2 + b a ) 2ab-a^{2}-b^{2}-a+b+2-(2ab-a^{2}-b^{2}+b-a)

= 2 a b a 2 b 2 a + b + 2 2 a b + a 2 + b 2 b + a ) =2ab-a^{2}-b^{2}-a+b+2-2ab+a^{2}+b^{2}-b+a)

= 2 =2

I would suggest to insert c = a b c=a-b to it.

Gian Sanjaya - 5 years, 9 months ago
John Lesteя Tan
Sep 4, 2015
  • The easiest way is you let
  • a=230495720348
  • b=1230487109384
  • c=230495720348 - 1230487109384
  • then now you can use the variables to compute for its value
  • (2-c)(c+1) -(1-c)(c)
  • 2
William Z
Aug 31, 2015

Since there are a lot of repetition, express the numbers like so:

x = 1 x=1

y = 230495720348 y=230495720348

z = 1230487109384 z=1230487109384

With these variables, you can rewrite the expression like so:

( y z + x + 1 ) ( z y + x ) ( x + y z ) ( x + z y 1 ) (y-z+x+1)(z-y+x)-(x+y-z)(x+z-y-1)

Multiplying this expression out yields 2 x 2x and since x = 1 x=1 , the answer is 2 .

Moderator note:

That's a great use of algebra!

Cannot see the question.The submission box is blocking it.

A Former Brilliant Member - 5 years, 8 months ago

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