A car is sent for an engineer from the factory every day that arrives at the railway station, the same time as the train he takes. One day he arrives at the railway station one hour before his usual time and without waiting for the car, he started walking towards the factory, he met the car and reached the factory 10 minutes before his usual time. How long did he walk (in minutes) before he reached the car?
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If the car meets the engineer n minutes before the regular train arrives, they will reach the factory 2 n minutes earlier than usual since they don't have to travel the final n minutes to the train station and back to the meeting point. We are told that 2 n = 1 0 so n = 5 . Having arrived an hour before the regular train, the engineer was walking for 6 0 − 5 = 5 5 minutes before meeting the car.