A train moving 45 miles per hour meets and is passed by a train moving 36 miles per hour. A passenger in the first train sees the second train take 6 seconds to pass him. How long is the second train in feet?
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The speed of the passenger in the first train, in relation to the movement of the second train, is 45 + 36 = 8 1 miles per hour.
or
5280 × 81 divided by 60 × 60 = 1 1 8 . 8 feet per second
Therefore, the length of the second train is 6 × 118.8 = 7 1 2 . 8 feet