How many 2's

There is only one positive integer less than 100000 that has exactly 17 number of positive factors (inclusive of 1 and itself). This number can be expressed as 2 2 2 2 2 2 n number of 2’s \underbrace{2^{2^{2^{2^{2^{\cdot^{\cdot^2}}}}}}}_{n \text{ number of 2's}} .

Find n n .


The answer is 4.

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1 solution

Saya Suka
Jan 12, 2017

17 = 16 + 1.
The number must be 2^16.
16 = 2^4 = 2^[2^2].
2^16 = 2^2^2^2, thus n = 4.


you got it

A Former Brilliant Member - 4 years, 4 months ago

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