How many 8s are needed?

Algebra Level 2

Using only the operations of addition and concatenation, what is the minimum number of 8's that we need to form a total of 1000?

13 8 6 4 10

Hana Wehbi by Hana Wehbi , 51, USA

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1 solution

Hana Wehbi
Nov 16, 2017

888 + 88 + 8 + 8 + 8 = 1000 888+88+8+8+8=1000

1 Helpful 0 Interesting 0 Brilliant 0 Confused

What operations are allowed? I could even define a function f f such that f : R → 1000 f : \mathbb R \to 1000 . So I just need to just one 8 to make a total of 1000, namely, f ( 8 ) = 1000 f(8) = 1000 .

Pi Han Goh - 3 years, 6 months ago

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I did specify that you need more than one 8. If I change the word total into sum, then it would be very easy to know the solution, right. I am open minded for any suggestion you have for me.

Hana Wehbi - 3 years, 6 months ago

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