How many answers?

Probability Level pending

How many solutions does the equation x 1 + x 2 + x 3 + . . . . . . . + x 20 = 10 x_{1}+x_{2}+x_{3}+.......+x_{20}=10 have, given that every x k x_{k} is an integer and 0 ≤ x k ≤ 10 0 \le x_{k} \le 10 for all k k ?

29!/(19!x10!) 200 20!/10! 20!/(10!x10!)

João Malheiros by joão malheiros , 20, Brazil

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