Paul has 13 red boxes and each one is empty or contains 7 blue boxes. Each blue box is empty or contains 7 green boxes. If it has 145 empty boxes, how many boxes does it have in total?
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Let's work through this backwards, starting with 1 3 red boxes and adding green and blue boxes. We have 1 3 empty boxes and 1 3 boxes total. First, let's add 7 blue boxes to a red box (because that is the only thing we can do). We now have a total of 2 0 boxes total (because we added 7 ), but when we added the blue boxes, one of the red boxes became full. Therefore, we only added 6 empty boxes (or rather, we added 7 empty boxes and filled 1 other, so there was a net of 6 added empty boxes). In fact, every time you add 7 boxes to any box, you add 7 boxes total and 6 empty boxes total. So, after n times, the total of boxes will be 1 3 + 7 n , while the total of empty boxes will be 1 3 + 6 n .
Now, we are given that 1 3 + 6 n = 1 4 5 . This can be solved to find that n = 2 2 . Plugging this into 1 3 + 7 n to find the total number of boxes, we find that there are 1 6 7 total boxes.