How many children?
A father in his will left all his money to his children in the following manner:
$1000 to the first born and 1/10 of what then remains, then $2000 to the second born and 1/10 of what then remains, then $3000 to the third born and 1/10 of what then remains, and so on.
When this was done each child had the same amount. How many children were there?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
Let total amount = $X, and number of children =n. Since the amount with all the children are equal, each one will get $X/n. Now the first child gets 1000 + ( X - 1000 )/10 = X/n. for the second child, 2000 + ( X - X/n - 2000)/10 = X/n. solving for X/n we get $9000. substituting X/n in first equation, we get X = $81000 which gives n = 9 .