How many chocolates?

15 $ ──────── get 15 chocolates (& get fifteen wrappers)
15 wrappers ─── get 5 chocolates (& get five wrappers )
3 wrappers ─── get 1 chocolate (& get one wrapper )
3 wrappers(1+ balanced 2) ──get 1 chocolate
So it becomes 15 + 5 + 1 + 1 = 22

first you will buy 15 chocolate which will give you 15 wrapper ,by which you will take 5 chocolate then you will have 5 wrapper by which you can purchase 1 more chocolate with two wrapper left. when you have eaten that chocolate then you can buy one more chocolate that is 15+5+1+1=22

First you will buy 15 chocolates by 15$. then exchange "3 wrappers for 1 chocolate" 15/3=5 chocolate > You will have now 5 new chocolates. exchange "3 wrappers for 1 chocolate" 5/3=1 new chocolates and have already 2 wrappers exchange "3 wrappers for 1 chocolate" 3/3=1 new chocolates now you have 1 wrappers but you can not exchange it :( ! final answer : 15 + 5 + 1 + 1 = 22

First You have $15, so 15 chocolates. Then you can exchange 3 wrappers for 1 chocolate, so you will have 5 more chocolates, 15+5=20 Then you have 5 wrappers because you 5 more wrappers that will make 1 more chocolate (you can only 3 wrappers, you have 2 wrappers left), so, 20+1=21 Now you got 1 more chocolate i.e. 2+1=3 wrappers, which will give you 1 more chocolate,so, 21+1=22, there it is!