How Many Chords?
Geometry
Level
3
Put
points on the circumference of a circle. What is the largest number of intersections for the chords?
The problem can’t be solved.
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1 solution
We need 4 points to have two intersecting chords. Thus, the answer is ( 4 N ) . Let N = 2 0 1 8 , we get ( 4 2 0 1 8 ) = ( 2 0 1 4 ! × 4 2 0 1 8 ! = 4 2 0 1 8 × 2 0 1 7 × 2 0 1 6 × 2 0 1 5 )