Find the number of digits of 8 2 5 .
You may use the approximation lo g 1 0 2 = 0 . 3 0 1 0 .
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Typos: "Number of digits in" and ⌊ 7 5 lo g 1 0 2 ⌋
Neat solution! +1
But here's something to note, to represent the floor function use \lfoor and \rfloor as I edited you solution. Click toggle latex if you didn't get it. Thanks!
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What's Toggle Latex?
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It is present in the menu on your profile pic. Try clicking it, you will understand it's use ;)
8 2 5 = 2 7 5 = 3 2 7 6 8 5 = 3 3 7 7 8 9 3 1 8 6 2 9 5 7 1 6 1 7 0 9 5 6 8 , so the numbers of didits of 3 3 7 7 8 9 3 1 8 6 2 9 5 7 1 6 1 7 0 9 5 6 8 is 2 3 .
And 3 3 7 7 8 9 3 1 8 6 2 9 5 7 1 6 1 7 0 9 5 6 8 can be read as thirty-three sextillion seven hundred seventy-eight quintillion nine hundred thirty-one quadrillion eight hundred sixty-two trillion nine hundred fifty-seven billion one hundred sixty one million seven hundred nine thousand five hundred sixty eight.
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Number if digits in 8 2 5 = ⌊ 2 5 lo g 1 0 8 ⌋ + 1 = ⌊ 5 lo g 1 0 2 ⌋ + 1 = ⌊ 7 5 × 0 . 3 0 1 ⌋ + 1 = ⌊ 2 2 . 5 7 5 ⌋ + 1 = 2 3
Note ⌊ . ⌋ represents the floor function