How many digits?

Algebra Level 2

Find the number of digits of 8 25 8^{25} .

You may use the approximation log 10 2 = 0.3010 \log_{10} 2 = 0.3010 .


The answer is 23.

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2 solutions

Number if digits in 8 25 = 25 log 10 8 + 1 = 5 log 10 2 + 1 = 75 × 0.301 + 1 = 22.575 + 1 = 23 8^{25}=\lfloor 25\log_{10}8\rfloor +1=\lfloor 5\log_{10}2\rfloor +1=\lfloor 75\times0.301\rfloor +1=\lfloor 22.575\rfloor +1=\boxed{23}

Note . \lfloor .\rfloor represents the floor function

Typos: "Number of digits in" and 75 log 10 2 \lfloor 75 \log_{10} 2 \rfloor

Hung Woei Neoh - 5 years, 1 month ago

Neat solution! +1

But here's something to note, to represent the floor function use \lfoor and \rfloor as I edited you solution. Click toggle latex if you didn't get it. Thanks!

Sravanth C. - 5 years, 2 months ago

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What's Toggle Latex?

Abhiram Rao - 5 years, 2 months ago

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It is present in the menu on your profile pic. Try clicking it, you will understand it's use ;)

Sravanth C. - 5 years, 2 months ago
. .
Feb 18, 2021

8 25 = 2 75 = 3276 8 5 = 33778931862957161709568 8 ^ { 25 } = 2 ^ { 75 } = 32768 ^ { 5 } = 33778931862957161709568 , so the numbers of didits of 33778931862957161709568 33778931862957161709568 is 23 \boxed { 23 } .

And 33778931862957161709568 33778931862957161709568 can be read as thirty-three sextillion seven hundred seventy-eight quintillion nine hundred thirty-one quadrillion eight hundred sixty-two trillion nine hundred fifty-seven billion one hundred sixty one million seven hundred nine thousand five hundred sixty eight.

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