Nigel and Shawn are both electricians. Nigel charges $15 for a service call, plus $15 per hour. Shawn charges $35 for a service call, plus $10 per hour. If they work the same number of hours and are paid the same amount of money, how many hours did they work?
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Can you plz Explain theoretically??? Then you owe me respect.........................
gud one
nice
s thats rit
crct
smpl
15+15x=35+10x => 5x=20 => x=4 hr.
15+15y=35+10y => 5y=20 => y=4 ans
use the options
15x + 35x =15 +10
15 + 15x = 35 + 10x
45/15=3
15+15x=35+10x therefore x = 4 ans.
15+15 hour=35+10 hour so hour=4.
4
4
The answer is 4 hours : 1st get 15+15X4=75 2nd get 35+10X4=75 Then the answer is 4 hours
4 thaku
that is what i did
let the working hour is x then according to the statement 15 + 15/x= 35 + 10/x taking LCM 15x+15/x = 35x+10/x by cross multiplication 35xsquare+10x=15xsquare+15x simplifying further we get x=1/4 ......
15+(15 hours)=35+(10 hours) (15 hours)-(10 hours)=35-15 (5*hours)=20 hours=20/5=4 thats all 4 hours is the answer
Let x be the number of hours they've worked.
1 5 + 1 5 x = 3 5 + 1 0 x → 5 x = 2 0 → x = 4
Therefore, they both worked for 4 hours .
Plug in n = 3, 4, 5, 6 until 15+15n = 36+10n = 75. Who needs algebra?
Suppose they work for X hrs. For Nogel dollar earned are 15 + 15 X anf for Shawn it is 35 + 10X since both earn equal so 15 + 15X = 35 + 10 X so X = 4 Hrs Ans
K.K.GARG,India
Excluding the charges of service call for Nigel and Shaun i.e. $15 and $35 we can say that Nigel worked for 4 hrs (Amt. earned=15+15+15+15) and Shaun also works for 4 hrs similarly (Here, amt. earned=10+10+10+10 ). Both earn the same grand total of amt.$75 respectively as they work for equal number of hours with respect to their difference in service call charges.
15+15x=35+10x => 5x=20 => x=4 hr..
Different between payment per hour : 15-10 =5
For first hour : A= 30 , B=45
45-30 = 15 = 3(5)
So they worked for 1+3 hours.
3 10+30 = 3 15+15
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15+15x=35+10x => 5x=20 => x=4 hr.. (ans)