In a class of 1 5 0 students, 9 0 % love singing, 8 6 % love dancing, 8 0 % love acting and 7 4 % love studying. Then what is the minimum number of students who love all the mentioned activities?
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Where is said that the populations are distinct? It’s nowhere said that who loves math only loves math. Therefore it’s legit to assume that all ones that love math may love anything else, and so 74% of 150 = 111 should be the answer.
Consider the following sets:
A: Students who love singing
B: Students who love dancing
C: Students who love acting
D: Students who love studying
The number of students that do not like all these four activities is given by ∣ ( A ∪ B ∪ C ∪ D ) c ∣ = ∣ ( A c ∩ B c ∩ C c ∩ D c ) ∣ , where the equality holds due to De'Morgan's Law. An upper bound is given by
∣ ( A c ∩ B c ∩ C c ∩ D c ) ∣ ≤ ∣ A c ∣ + ∣ B c ∣ + ∣ C c ∣ + ∣ D c ∣
∣ ( A c ∩ B c ∩ C c ∩ D c ) ∣ ≤ . 1 ∗ 1 5 0 + . 1 4 ∗ 1 5 0 + . 2 ∗ 1 5 0 + . 2 6 ∗ 1 5 0
∣ ( A c ∩ B c ∩ C c ∩ D c ) ∣ ≤ 1 0 5
To find the minimum number of students that love all the activities, we assume that A c , B c , C c , and D c are disjoint. Consequently, at the most 105 students do not love all these four activities. We conclude that at least 150 - 105 = 45 students love all the activities.
First of all find the percent of all students who loves each things i.e. love singing = 90% so total no. of students who love singing = 90/100 * 150 = 135.
love dancing = 86% so total no. of students who love dancing = 86/100 * 150 = 129.
love acting = 80% so total no. of students who love acting = 80/100 * 150 = 120.
love studying = 74% so total no. of students who love studying =74/100 * 150 =111.
now subtract each of the solution with total i.e. with 150. After subtraction you will get the following solutions...15...21...20...39. now sum up these numbers and subtract form total .....i.e. (150)-(105) = 45 and that's the solution. :)
Minium percentage of student who love...
Singing and Dancing : 1 0 0 − ( 1 0 0 − 9 0 ) − ( 1 0 0 − 8 6 ) = 7 6
Singing, Dancing and Acting : 1 0 0 − ( 1 0 0 − 7 6 ) − ( 1 0 0 − 8 0 ) = 5 6
Singing, Dancing, Acting and Studying(All) : 1 0 0 − ( 1 0 0 − 5 6 ) − ( 1 0 0 − 7 4 ) = 3 0
Hence, the answer is 1 5 0 . ( 0 . 3 ) = 4 5
Exactly I did ot the same way ;)
I like your solution :D
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The percentages who don't love these activities are 10%, 14%, 20%, and 26%, resp.. If these populations are distinct, then the percentage who loves everything is 100%-10%-14%-20%-26%=30%, or, 4 5 students.