Y intercept(a) - 5 units , X intercept(b) - 7 units
D is the diameter of bigger circle and d diameter of smaller circle .
Find d + D
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Let us first focus on the inscribed circle and the right triangle. Lines AB and BC are tangent lines of the circle at points G and E respectively. Thus angle(FGB) and angle(FEB) are both right angles. Lines GF and FE are both the radii of the circle. Hence, GF=FE. Since GF=FE, angle(FGB)=angle(FEB)=angle(GBE)= 90 degrees Therefore, GFEB is a square. Let each side of the square be of length x.
ON TRIANGLES AGF and ADF, a.) GF=FD (both are radii) b.) angle(AGF)= angle(ADF)= 90 degrees (tangent) c.) AF=AF Hence, by Pythagorean theorem, AG= AD = 5-x
SIMILARLY ON TRIANGLES CDF and CEF, CD= EC= 7-x
BY PYTHAGOREAN THEOREM ON TRIANGLE ABC (with AB=5 and BC=7) AC= sqrt(74) AD+DC= sqrt(74) 5-x+7-x = sqrt(74) 12-2x= sqrt(74) 2x= 12-sqrt(74) = d
Now, let us move on to the larger circle with the right triangle inside. We can move the right triangle inside such that point B together with points A and C touches the circle. With that we now have AC as the diameter of the larger circle. AC= sqrt(74) = D
Therefore, d+D= 12-sqrt(74) + sqrt(74) = 12