How many numbers?

If the number is divisible by both 2 and 3 it will be divisible by 6.

$16 \times 6 = 96$

$17 \times 6 = 102$

So there are 16 numbers under 100 that are divisible by both 2 and 3.

floor(100/(2x3)) = 16

We know numbers that can be divided by 2 and 3, can be divided by 6.. Setting up arithmetic progression 6,12,18,... 96. Find the number of terms using the formula

Tn = a + (n-1)d

96 = 6 + (n-1)(6)

n=16

find the largest number divisible by the common multiple of 2 and 3 { $6$ } less than 100, which is 96 and divide it by 6 $\boxed{\frac {96}{6} = 16}$ and so we deduce that there are 16 numbers less than 100 divisible by both 2 and 3.

if a number is to be divisible by 2 and 3,then it is divisible by 2x3=6
so the numbers below 100 divisible by 6 are 17 (16 if 0 is excluded)

0,6,12,18,24,30,36,42,48,54,60,66,72,78,84,90 & 96