Let be a 4-digit integer such that the last digit unknown.
If we are told that this integer is divisible by 3 and has all distinct digits, how many possible solutions of are there?
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The integer has to be divisible by 3, so sum of its digits should be divisible by 3, too. 3 + 6 + 9 = 18. It is already divisible by 3, so D could be 0, 3, 6, 9. But since the integer’s digits have to be distinct, it can be only 0. There is only 1 solution of D.