How many problems to do?

Algebra Level 1

AMAN has some problems to work on. SAVIO has twice as many problems to work on as AMAN has. ADITYA has twice as many problems to work on as SAVIO has. If they have 476 problems to work on altogether, how many problems does SAVIO+AMAN have to work on?

Details and assumptions:

The problems that they are working on are all different from each other.

156 333 204 356

Aditya Raj by Aditya Raj , 22, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Nick Byrne
Feb 7, 2015

Let Aman be M, Savio be S, Aditya be A.

- S = 2 × M S=2 \times M

- A = 2 × S A=2 \times S

So A = 4 M A=4M

"they have 476 problems to work on altogether"

A + S + M = 476 A+S+M=476

( 4 M ) + ( 2 M ) + M = 476 (4M)+(2M)+M=476

7 M = 476 7M=476

M = 68 M=68

S = 136 S=136

A = 272 A=272

S + M = 204 S+M= 204

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Hello,

let the problems = x,

AMAN = x , as x = 68

SAVIO = 2x = 136

ADITYA = 4x = 272

Total = 476 = x + 2x + 3x = 7x,

x = 476 / 7 = 68,

therefore , AMAN + SAVIO = configure yourself.... thanks....

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...