How many students are in this school?

If we had $7$ students less, the number of students would have been divisible by $12,20,36$ separately.

The smallest number divisible by $12,20,36$ is their least common multiple which is: $\operatorname{lcm}( 12,20,36)=180.$

So the number of students will be a number of the form $180n+7$ . To find this $n$ we have to use the fact that the number of students is between $500$ and $600$ , so by trying we find that $n=3$ .

Therefore the number of students is: $180\cdot3+7=540+7=\boxed{547}$ .

Whatever divisible by 36 is also divisible by 12.

The only possible numbers between 500 & 600 & divisible by 20 are: 520, 540, 560 & 580. Only 540 is divisible by 12 as well.

So the final number is 540 + 7 = 547.

Here, LCM of(12,20,36) is 180. now, 180 * 2 +7 = 367 180 * 3 +7 = 547 180 * 4 +7 = 727 so,the number of students is : 547(ans)

we are given that when the children are divided in groups of 12,20 or 36, 7 are still left and the total no of children is between 500-600. so, first, we need to take out the lcm of these nos. ie. LCM(12, 20, 36)=180 we now have 180 as the LCM. we will now find the multiple of 180 between 500 and 600 that is 540. adding 7 to it would give us the answer! therefore, the answer is 540+7=547

find a common multiple of 12, 20 and 36 which is between 500-600. that is 540. And as there are still 7 students remaining so add them to get total 547

find LCM of 20, 12 and 36.......you will get 4x5x9x3=540...since if divided by 20, 12 or 36 will have remainder 7 , simply add 7 to 540 therefore = 547.....^^

Very easy.

We need to look at a factor which is divisible by 12,20,36. There is another condition, the factor must be in between 500 and 600. 20 is the easiest to divide among these numbers.

Thus, we first look at 520. It is divisible by 20, but not 12. Hence, it can't be a common factor. Then, we look at 540. The number is divisible by 12,20 and 36. Henceforth, it is a common factor of all the numbers. We know that there are 7 students who remain. Therefore the number of students in the class must be 540+the remaining, ie 547 students. :)

540 is the number between 500 and 600 and it can be divided by 12,20 and 36.so the answer is (540+7)=547

(12 , 20 , 36 ) / 2 = ( 6 , 10 , 18) ( 6 , 10 , 18) / 2 = ( 3, 5, 9) now, 3 5 9 = 135

135 * 2 = 270 270 * 2 = 540 so, 540 + 7 = 547