How many terms?

Let 200 ! = A × 1 0 k 200! = A \times 10^k , where A A and k k are positive integers , and A A is not a multiple of 10.

Find the number of distinct terms in the expansion of ( a + b + c ) k (a+b+c)^k .


The answer is 1275.

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1 solution

Md Zuhair
Sep 7, 2016

We will see that 200 ! 200! has 49 49 zeroes. Then ( a + b + c ) 49 (a+b+c)^{49} . then we will see all the terms are in AP and their sums will be 1275. 1275.

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Calvin Lin Staff - 4 years, 9 months ago

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Thank you for the information.

Md Zuhair - 4 years, 9 months ago

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