How many triangles are in the figure above?
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We can break up the cases in terms of what kinds of vertices the triangle has.
(1) All blue vertices.
There is 1 triangle for each set of 3 of the blue vertices, so there are ( 3 5 ) = 1 0 of these type.
(2) Two adjacent blue vertices, one red vertex.
For each pair of adjacent blue vertices, there are 3 such triangles (see below). Thus, there are 5 ⋅ 3 = 1 5 triangles of these type.
(3) Two non-adjacent blue vertices, one red vertex.
For each pair of non-adjacent blue vertices, there is 1 such triangle (see below). Thus, there are 5 ⋅ 1 = 5 triangles of these type.
(4) One blue vertex, two red vertices.
For each blue vertex, there is 1 such triangle (see below). Thus, there are 5 ⋅ 1 = 5 triangles of these type.
(5) All red vertices.
No such triangles exist!
Thus, the total number of triangles is 1 0 + 1 5 + 5 + 5 = 3 5 triangles.