How much?

Chemistry Level 2

In a beaker containing 2 liters of 3 normal solution of pure sodium hydroxide, how much hydrochloric acid of the same volume must be added to neutralize all of sodium hydroxide contained in it?

Submit your answer in grams (g).


The answer is 219.

Ashish Menon by Ashish Menon , 20, India

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1 solution

Ashish Menon
Apr 27, 2016

For neutral solution,
N 1 × V 1 = N 2 × V 2 N_1 × V_1 = N_2 × V_2 where N is normality and V is volume.
N 1 × 2 = 3 × 2 N 1 = 6 2 N 1 = 3 N_1 × 2 = 3 × 2\\ N_1 = \dfrac{6}{2}\\ N_1 = 3
Let x x be the weight of hydrochloric acid required. Now, basicity of H C l HCl is 1.
Number of moles of H C l HCl required = x 36.5 \dfrac{x}{36.5} (because molecular weight of HCl is 36.5)
N = Number of moles × Basicity Molecular weight × Volume 3 = x × 1 36.5 × 2 3 = x 73 x = 3 × 73 x = 219 N = \dfrac{\text{Number of moles} × \text{Basicity}}{\text{Molecular weight} × \text{Volume}}\\ 3 = \dfrac{x × 1}{36.5 × 2}\\ 3 = \dfrac{x}{73}\\ x = 3 × 73\\ x = \boxed{219}


10 Helpful 3 Interesting 3 Brilliant 1 Confused

N2=3. ??????????

Parth Chopra - 5 years ago

You dont understand the problem correctly

Laisa Binu - 1 year, 9 months ago

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