The dimension of a rectangular television screen is given as the diagonal length (in centimeters). What is the dimension of a rectangular television screen which has a length of 80 centimeters and a width of 60 centimeters?
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c^2 = a^2+b^2 = sqrt[(80cm)^2+(60cm)^2] = sqrt(10000cm^2) = 100 cm
ex : x = dimension
x" = p" + q" x" = 60" + 80" x" = 3600 + 6400 x" = 10000 x = 100
Since the length of the a rectangular television screen is given as the diagonal length (in centimeters) of it, then it equal to square root of [(60 centimeters)^2+(80 centimeters)^2]=100 cen timeters.
Simple just view the diagonal of a rectangle and you would come up with Pythagoras Theorem. Then substitute the values to get the answer 100.
The diagonal of a rectangle divides it in two right triangles...
By Pythagorean theorem, we know that,
( H y p o t e n u s e ) 2 = ( L e g 1 ) 2 + ( L e g 2 ) 2
Here, in the rectangle, we can model the dimension as hypotenuse and the length of the two sides as the legs of a right triangle... Plugging in the values... We get,
( H y p o t e n u s e ) 2 = ( 8 0 c m ) 2 + ( 6 0 c m ) 2 = 6 4 0 0 c m 2 + 3 6 0 0 c m 2 = 1 0 0 0 0 c m 2
H y p o t e n u s e = 1 0 0 0 0 c m 2 = 1 0 0 c m
Hence, the required dimension value is 1 0 0 ...
root over [60^2]+[80^2]= root over [10000]=100
If we put a diagonal(length) on a rectangle, it forms 1-2 triangles then, By Pythagorean Theorem: a^2+b^2=c^2 ( ^ as exponent ) So, 80^2+60^2= c^2 80^2+60^2= 10,000 Then we will find the square root of 10,000 to know it's diagonal length or hypotenuse: √10,000 = 100
using Pythagoras theorem: dimension= sqr root((60^2)+(80^2))= sqr root (10000) = 100
Take 80^2 cm + 60^2 cm and square root it. The answer you will get is square root 10000cm, which is 100 cm.
Let ABCD be the rectangular T.V. Let AB = 80cm , BC = 60cm and AC be the diagonal. By Pythagorean theorem , AC = (6400 + 3600)/100= 10000/100= 100cm
a^2+ b^2 = c^2 6^2+8^2=36+64 100 =10^2
I like how you are hinting at an approach which doesn’t require us to square such large numbers. Simplifying the initial algebra can help us avoid careless mistakes.
Triple phitaghoras 60,80,100
Pelo teorema de Pitágoras: a^2=b^2+c^2 ; onde "a" é a hipotenusa e "b" e "c" são os catetos. Sendo assim: a^2=60^2+80^2
a^2=3600+6400
a^2=10000
a=100
Bem explicado, vlw!!!
diagonal=square root of ((80^2)+(60^2))
use the Pythagorean Theorem : a 2 + b 2 = c 2
8 0 2 + 6 0 2 = c 2
6 4 0 0 + 3 6 0 0 = c 2
1 0 0 0 0 = c 2
c = 1 0 0 0
c = 1 0 0
Thus the answer is 100
80 * 80+60 * 60=10000 ,the square root of 10000 is 100
c 2 = a 2 + b 2 = 80 2 + 60 2 = 6400 + 3600 c 2 = 10000 c= square root of 10000 c = 100
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To get the length of diagonal, we first add the square of the nos. and then take a square root of it. =80`2 + 60^2 =10000 Now take root of it . So it is 100