How much is my partner worth?

Algebra Level 2

x 2 + y 2 + x y = 18 x + y + x y = 6 x + y x y = ? \begin{aligned}x^2 + y^2 + xy&=& 18\\ x + y + \sqrt{xy}&=& 6 \\ x + y - \sqrt{xy} &=& \ ? \end{aligned}

Don't be shy to post your solutions if you have a different method!


The answer is 3.

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5 solutions

Noel Lo
May 6, 2015

( x + y + x y ) ( x + y x y ) = ( x + y ) 2 x y = x 2 + y 2 + x y (x + y + \sqrt{xy})(x + y - \sqrt{xy}) = (x + y)^2 - xy = x^2 + y^2 + xy

6 ( x + y x y ) = 18 6(x + y -\sqrt{xy}) = 18

x + y x y = 18 6 = 3 x + y - \sqrt{xy} = \frac{18}{6} = \boxed{3}

my solution is this... x + y + √xy = 6 can be written as .. x + y = 6 - √xy............ Then by manipulating the first equation x² + y² + xy = 18... we can do.. x²+ y² + xy + xy = 18 + xy.. to have x² + 2xy + y² = 18 + xy or (x + y)² = 18 + xy........ by using (x + y)² = 18 + xy we can also use the value x+ y = 6 - √xy...... then ... (6-√xy)² = 18 + xy....... by expanding the value on the parenthesis.... 36 - 12√xy + xy = 18 + xy...... by combining like terms the remaining would be - 12√xy = -18...... there fore √xy = 3/2............. solving 2nd equation x + y + 3/2 = 6.. there fore x + y = 9/2......... solving the third equation x + y - √xy = ? ... given the value of x + y = 9/2 and √xy = 3/2.... the final equation is 9/2 - 3/2 = 6/2 or 3

Jeca Ehnok - 6 years, 1 month ago

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Good!!! Interesting!!!

Noel Lo - 6 years, 1 month ago

Check your expansion of (x +y)^2. You should get: x^2+2xy+y^2.

John Church - 6 years, 1 month ago

For completeness, are there values of x x and y y that will satisfy your equations?

Calvin Lin Staff - 6 years, 1 month ago

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x = 1 4 ( 9 + / 3 5 ) x = \frac{1}{4} (9 +/-3\sqrt{5}) and y = 1 4 ( 9 / + 3 5 ) y = \frac{1}{4} (9 -/+ 3\sqrt{5})

Noel Lo - 6 years, 1 month ago

Very clever answer...Keep it up.

Ubaidullah Khan - 6 years, 1 month ago
Khalid Sadek
May 10, 2015

you just multiply the second and third equations then you'll find the result is 18/6 = 3

yeah right.. I'm thinking that the second to the last equation has no basis.... where did he get that one?

Jeca Ehnok - 6 years, 1 month ago

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It is just a random equation. You need two equations to determine the value of a third expression.

Noel Lo - 6 years, 1 month ago
Trần Tân
May 14, 2015

square the 2nd-equality , arrange to appear 1st-equality ->value of √xy -> sholve

Kenneth Gibson
May 13, 2015

x^2 + y^2+ xy = 18 (x + y)^2 = 18 + xy x + y = 6 - sqrt(xy) (6 - sqrt(xy))^2 = 18 + xy 36 - 12(sqrt(xy)) + xy = 18 + xy 36 - 12(sqrt(xy)) = 18 sqrt(xy) = 1.5 x + y = 4.5 x + y - sqrt(xy) = 3

Gerardo Lozada
May 10, 2015

x+y+sqrt(xy)=6 or sqrt(xy)-6=-(x+y), squaring both sides and rearranging yields x^2+xy+12sqrt(xy)+y^2=36. Subtract x^2+y^2+xy=18 from this yields 12sqrt(xy)=18 or sqrt(xy)=3/2 which yields x+y+3/2=6 or x+y=9/2. Finally x+y-sqrt(xy) = 9/2-3/2 = 3.

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