How much Rope can be there?

A rope rests on two platforms that are both inclined at an angle θ \theta (which you are free to pick), as shown above. The rope has uniform mass density, and its coefficient of friction with platform is 1. The system has left-right symmetry. What is the largest possible fraction of the rope that does not touch the platforms?

2 1 2 + 1 \frac { \sqrt { 2 } -1 }{ \sqrt { 2 } +1 } 2 + 1 2 1 \frac { \sqrt { 2 } +1 }{ \sqrt { 2 } -1 } 2 2 + 1 \frac { \sqrt { 2 } }{ \sqrt { 2 } +1 } 2 + 1 2 \frac { \sqrt { 2 } +1 }{ \sqrt { 2 } }

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1 solution

Ashwin Gopal
May 23, 2015

This is a famous equilibrium problem. One of the approach is by considering the rope as 3 blocks having mass kx,ky and kx where k is mass per unit length and x is length lying on inclined plane and y be the length of hanging part. Now draw FBD and solve for equilibrium condition. U will get fraction as f = ( F ( θ ) / [ F ( θ ) + 1 ] ) w h e r e F ( θ ) = ( sin θ × cos θ sin θ 2 ) f=(F(\theta)/[F(\theta)+1]) where F(\theta) = (\sin \theta\times \cos \theta - \sin \theta ^{2}) Now applying calculus, we get fraction.

Yups its a famous and innovative kinda problem..!! The first timers generally feel difficulty with it..!!

Rohit Gupta - 6 years ago

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There is very good solution to this problem in the Internet. (in PDF form)

Ashwin Gopal - 6 years ago

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