How much should this farmer produce ?.

Algebra Level 3

A farmer owns 1000 sqmetres of farm land. He wishes to produce both Potatoes and tomatoes. He can produce potatoes at the rate of 1kg per 50 sq metres of farm land , tomatoes at the rate of 1 kg/20 sq metres of farm land. After they are produced Tomatoes yield a profit of USD 1 per kg , whereas potatoes yield a profit of USD 2 per kg.

In order to maximize his profits How many Kgs of Potatoes and Tomatoes does the farmer have to cultivate ?.

You can assume that the farmer can use a maximum of 90 percent of his farm land for cultivation.

Linear Programming

10 Kg of Potatoes,20kgs of tomatoes 18 Kg Potatoes, 0 Kg tomatoes 4 kg of Potatoes, 35 kgs of tomatoes 45 Kgs of tomatoes, 0 kg Potatoes

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2 solutions

  • Potato: The farmer can produce 1 kg 1 \text{ kg} of potato with 50 m 2 50 \text{ m}^2 of land or 1 50 = 0.02 kg/m 2 \frac 1{50} = 0.02 \text{ kg/m}^2 which gives a profit of p p = 0.02 × 2 = $ 0.04 / m 2 p_p = 0.02 \times 2 = \$0.04/\text{m}^2 of land.
  • Tomato: The farmer can produce 1 kg 1 \text{ kg} of tomato with 20 m 2 20 \text{ m}^2 of land or 1 20 = 0.05 kg/m 2 \frac 1{20} = 0.05 \text{ kg/m}^2 which gives a profit of p t = 0.05 × 1 = $ 0.05 / m 2 p_t = 0.05 \times 1 = \$0.05/\text{m}^2 of land.

Since the farmer gets higher profit planting tomato per m 2 \text{m}^2 of land, he obviously plants all land available with tomato. That is to produce 1000 × 90 % × 0.05 = 45 kg 1000 \times 90 \% \times 0.05 = 45 \text{ kg} of tomato and 0 kg \text{ 0 kg} of potato.

Srinivasa Gopal
Aug 6, 2018

Let X be the kgs of Potatoes and Y be the kgs of tomatoes that the farmer has to produce.

The profit function can be written as Y + 2X. This is shown in the graph above as family of lines with Y + 2X = K.

The constraint on the production is the utilization of the cultivatable area. The total cultivatable area for producing Xkgs of Potatoes and Y kgs of tomatoes can be represented by the function 50* X + 20 * Y. Since the maximum possible cultivatable area is 900 sq metre. The constraint to farm production can be written as 50 * X + 20* Y <= 900.

This is shown in the graph above. The maximum value of Y + 2X occurs when Y = 45 with a maximum profit of USD 45. In other words to achieve maximum profit the farmer has to cultivate 45 kgs of tomatoes.

Linear Programming

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