How much time to fill?

Geometry Level 3

A cylindrical water tank of diameter 1.4 m and height 2.1 m is being fed by a pipe of diameter 3.5 cm through which water flows at a rate of 2 metres per sec. In how much time will tank be filled (in minutes)?

Click Here for more from this set.


The answer is 28.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Vignesh Rao
Dec 23, 2015

Volume of cylindrical tank = π r 2 h = ( π × 70 × 70 × 210 ) cm 3 \pi r^2 h = ( \pi \times 70 \times 70 \times 210) \text{ cm}^3 ...(i)

Volume of water added in each second = Area of cross section of pipe × Rate of water flow \text{Area of cross section of pipe} \times \text{Rate of water flow}

( π × 3.5 2 × 3.5 2 ) cm 2 × ( 200 ) cm/sec \Rightarrow (\pi \times \frac{3.5}{2} \times \frac{3.5}{2})\text{ cm}^2 \times (200)\text{ cm/sec} ...(ii)

Time taken to fill = Eqn. (i) Eqn. (ii) ( π × 70 × 70 × 210 ) ( π × 3.5 2 × 3.5 2 × 200 ) = 1680 seconds = 28 minutes \frac{\text{Eqn. (i)}}{\text{Eqn. (ii)}}\\ \Rightarrow \frac{( \pi \times 70 \times 70 \times 210)}{(\pi \times \frac{3.5}{2} \times \frac{3.5}{2}\times 200)} = 1680 \text{ seconds} = 28 \text{ minutes}

time = volume volume flow rate = π 4 ( 1.4 ) 2 ( 2.1 ) π 4 ( 0.035 ) 2 ( 2 ) = 1680 seconds \text{time}=\dfrac{\text{volume}}{\text{volume flow rate}}=\dfrac{\dfrac{\pi}{4}(1.4)^2(2.1)}{\dfrac{\pi}{4}(0.035)^2(2)}=1680~\text{seconds}

But in 1 1 minute, there are 60 60 seconds, so the desired answer is 28 minutes 28~\text{minutes} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...