A cylindrical water tank of diameter 1.4 m and height 2.1 m is being fed by a pipe of diameter 3.5 cm through which water flows at a rate of 2 metres per sec. In how much time will tank be filled (in minutes)?
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time = volume flow rate volume = 4 π ( 0 . 0 3 5 ) 2 ( 2 ) 4 π ( 1 . 4 ) 2 ( 2 . 1 ) = 1 6 8 0 seconds
But in 1 minute, there are 6 0 seconds, so the desired answer is 2 8 minutes .
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Volume of cylindrical tank = π r 2 h = ( π × 7 0 × 7 0 × 2 1 0 ) cm 3 ...(i)
Volume of water added in each second = Area of cross section of pipe × Rate of water flow
⇒ ( π × 2 3 . 5 × 2 3 . 5 ) cm 2 × ( 2 0 0 ) cm/sec ...(ii)
Time taken to fill = Eqn. (ii) Eqn. (i) ⇒ ( π × 2 3 . 5 × 2 3 . 5 × 2 0 0 ) ( π × 7 0 × 7 0 × 2 1 0 ) = 1 6 8 0 seconds = 2 8 minutes