How old am I?

Let the number of years lapsed since 14 years old be $n$ , then we have:

$2(n+14)=n+42\quad \Rightarrow 2n+28=n+42 \quad \Rightarrow n = 42-28 = 14$ .

Therefore, the current age is $n+14=14+14=\boxed{28}$

The age between the guy and his father is 42- 14 = 28 . let the age of the guy be x and his father is twice of his age and is older than him by 28 years . So : 2(x) = x+28 , x = 28 .

when the son was born (suppose 0 yrs old) the father was 28 years old. so when the son will be 28 years old, father will be 28+28 = 56 years old. hence , when the son will be 28 years old, the father will be twice his age...

Difference of age = 42 -14 = 28, Let, present age = x years, x+ 28 = 2x, so, x = 28

Let us consider after x years my father's age will be twice of my age, So 2(14+x) = 42+x On solving above equation we get X=14 So my present age is 14+14= 28

current age of father =x;

14 years ago

x-14=42

x=56

current Son's age=x/2=28

if you apply proportion, that's too easy! start here:

14 - - - 42

x - - - 84

if you cross multiply, this will be the result: 42x=84(14) 42x=1176

then divide both by the value of x (cross out the 42 in the numerator and the denominator. the result will be: x=1176/42

which results to: x=28

I hope this is helpful

2x - x = 28
So x = 28

difference between ages=28 yrs. now when the son's age will be 28 yrs., his father's age has to be 56 yrs. thus, the answer is 28 yrs.!!#badamtuss

Draw a graph method x axis = my age y axis= dads age

when i was 14 my dad was 42, therefore plot (14,42) and by exprapolation: when i was 0 years old (born) my dad was 28, therefore plot also (0,28)

work out equation of line: (y=mx+c - you know it's a linear function!) gradient (m): (42-28)/(14-0) = 14/14 = 1 c intercept is 28

therefore you have y=x+28

you want to find when the father is twice sons age, therefore plot y=2x aswell

you can solve this visually or as a pair of simultaneous equations

via simult' eq'

2x=x+28

therefore x=28 therefore dads age =56

The trick is the age difference is always the same.

Lol that Cheong dude is smart. I just got it right trying to use simple logic. Took my all three tries though.

just add son's age in their ages i.e. 42+14=56,, 14+14=28 so,, u can see now father's age is double of that of son's,, son's current age is 28.. (if son's age was n,, thn father's 3n,, just add n in both,, thn it will be 2n & 4n thats it!!!)

14+x = 2(14+x) where x is the number of years passed. When solved, x=14. Now, add 14+14, and the person's age is 28.

Let the number of years that had passed since I was 14 be $y$ .

"When I was 14 years old, my father was three times my age." $\rightarrow F = 14 \times 3 = 42$

"Now, he is twice my age." $\rightarrow 42 + y = 2(14 + y)$

Solving the equation gives: $\begin{aligned} 42 + y &= 2(14 + y) \\ 42 + y &= 28 + 2y \\ 2y - y &= 42 - 28 \\ y &= 14 \end{aligned}$ So, my age is $14 + y = 14 + 14 = \boxed{28}$ .

Thus, the answer is 28 .

When I was $14$ years old, my father was $(14*3)=42$ years old.. So, When my father was $(42-14)=28$ years old, I was born.. Now, it can be easily said that when I will be $28$ , my father will be $(28*2)=56$ ..So, The answer is \boxed{\color\red{28}}

28 . twice of 28 is 56 and difference from 14 is 42 and same difference from 28 is 14. This was done by the trial and error method!! LoL

They asked the boys age, if his father who is 28 years older than him and is double the boys age the boy has to be 28. 42 - 14 = 28.

Given son age is 14 And father age is 42 He ask twice the sons age so 14×2=28 The current age is 28

Let x be the number of years in which my father age is becomes twice of my age Then, 2(14+x)=42+x , 28+2x=42+x , 2x-x=42-28 , x=14 , So, my age is. 14+14= 28

The difference btw their age will always be same so 42 - 14 =28 And now the father is twice the age of son Let son's age be x Father - 2x If we subtract these two the answer will be 28 So father - son = 2x-x 2x-x= 28 --> x=28

The condition of the age difference must hold for each year: let the father's age be ([n]+ 28)=0 years; such that the son's age x-n=28... The son is half his father's age; or the father is 2x the age of his son, hence: 2x-28=0....

2x-28+28=0+28, 2x=28; thus dividing both sides by 2... 2x/2=28/2, x=14; and we substitute: 2(14)+28=0 28+28=56. Again ([28]+28)=0, 28+28=56, thus if his father is 56 yrs of age; the son being half his age, then he must be 28 yrs of age.

Okay you may use a simpler solution as to tell how far apart they are: 42-14=28. In order to be twice as much, you would have to be twice the difference.

double the difference

So the kid never aged. That is kinda weird but got the answer any ways first try lol.

42-14=28,28+?=2*28

Let the age of the son is X and his father Y so Y-X=28 If we want Y=2X solving these two together X=28 Y=56 And difference still 28 for sure

Let $y =$ Years older

According to the question. In $y$ years the equation $42 = 3(14)$ becomes

$42 + y = 2(14 + y)$

We can expand it to get

$42 + y = 28 + 2y$

Re-arranging this gives us $y$

$y = 14$

So his current age is $14 + y$ which is equal to $28$ , so he is $28$ years old.

Let the guy is n and father is m n = 14, m=42, the diffetent of age is 28 if now m = 2n so n is . . . n+28 = 2n n = 28 so the age of guy is 28 years old

let f = father's age now m= my age now f=2m (eq.1); and the difference of their age now and the past should be equal(years lapsed), therefore, m-14=f-42 (eq.2). By substitution, m=28.

So I am 28 years old and my father 56 years old right now

My age = (14).....father's age 42, which is 3 times of (3 *14) difference should be 28 always..... so....lets make the formula.. x=me...y=my father equation is ......Y=x+28...substitute in following formula..you get answer. 2x=Y.....so....2x=x+28,........X=28..!!!!!!!!!!!!!!!!!!!!

let my age be X and my father age be Y
when X=14 , Y=42 the difference between our age = 42_14 = 28 years
Y=X+28
2X =Y
2X = X+28
2X _X =28
X =28

When the boy is 14 , his father become 42.after x years his father's age is twice his age.find the value of x and solve😎

age=x father's age=3x present age of x= twice the given age x=2x x = 2*14 x=28

42-14 = 28 Difference is 28. So at at 28, his father's age will be twice

2 (14+x)= 42+x , 28+x=42+x, x= 42-28=14 as a result x is the added years to current ages which means 14+14= 28 and 42+14=56.

2(n+14)=n+42 =>2n+28=n+42 =>2n-n=42-28 =>n=14 .'. present age = n+14 =14+14 =28

The difference between their age is 28. So If you let x be the age of the son then, x+28=2x. Therefore, x=28

2(14+x)=42+x 28+2x=42+x x=14 14+14= 28 years old

Equ 1: f-s=28 -> Equ 2: 2s=f -> Substituting: 2s-s=28 -> s=28

Let the present age of son is x.so the ratio will be 2x and 3x. the age difference will be 2x-14=3x-42 or x=28

for 3 my father's age42. &for 2 my fathers age 28. but age is ever be increased. so that will be the age.

step1. 2(x+14)=x+42 step 2 2x+28=x+42 step 3 2x-x = 42-28 step 4 x=14 so the age is x+14 which is equal to x= 28

simply just adding current years 2014 from when i was 14 years old

let the age of father be F and age of son be S. The age difference between father and son = F-S = 42-14 = 28.
Since F-S = 28; F=28+S; Solution: father's age is twice as sons i.e, F=2S; 28+S=2S; S=28 ; where S is the age of the son.

The age difference between the father and son would remain the same any time. ( unless they have a time paradox.)

So, if the age of son is x, then, Father's age = x +28, Now if we insert the conditions of the question, then 2x=x+28, x= 28.

let x be the no. of yrs after which the father is twice the age of his son.

so after x yrs, age of son = 14 + x.......... age of father = 42 + x..........

after x yrs father is twice the age of his son , so :

2 * (14 + x ) = 42 + x........ 28 + 2x = 42 + x........... x = 14..........

so the current age of the boy is 14 + x = 14 + 14 = 28..

take the fraction 3/42= 2/y where y is the known so by rearranging the fractions you get a formula that shows (42*2)/3 that equals 28 or you can solve the formula 2(x +14) = x +42

So we have x as a number of year is passed , a equation can be like :

2( x + 14 ) = x + 42 2x + 28 = x + 42 x = 14

Because it already passed 14 years , so we easily just plug it in x + 14

So we have : 14 + 14 = 28.