How to calculate nothing?

Algebra Level 3

We know that by Vieta's formula , the sum of roots of the equation x 5 + 4 x 4 + 3 x 3 + 2 x 2 + x + 1 = 0 x^5 + 4x^4 + 3x^3 + 2x^2 + x + 1 = 0 is -4. But what about the sum of positive roots of the same equation?


The answer is 0.

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2 solutions

Kushal Bose
Dec 4, 2016

The function f ( x ) = x 5 + 4 x 4 + 3 x 3 + 2 x 2 + x + 1 f(x)=x^5+4 x^4+3 x^3+2 x^2+x+1 .The value of f ( 0 ) = 1 f(0)=1 .

For every x 0 x \geq 0 the function will surely give positive value because every co-efficient is postive.So it will never intersect or cross X X- axis.So the number of positve roots are zero.Thus the sum of positive roots is zero.

P.S. There is at least one negative root should be there

I think if the equation didn't have "-" (negative). So i think there is no positive root

So like (x-1)^2 which is x^2 -2x +1 There is negative sign so it's has positive root which is 1

But unlike (x+1)^2 = x^2+2x+1 No negative sign no positive root

see Descartes' Rule of Signs

You are observing the descartes' rule of signs !

Nihar Mahajan - 4 years, 6 months ago

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Ah thank you so much, finally i know the rules

Daniel Sugihantoro - 4 years, 6 months ago

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The more you learn :)

Calvin Lin Staff - 4 years, 6 months ago

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