Given that, how many folds would be required to reach the Moon?
Details and Assumptions:
Distance to the Moon: km / miles
*observable Universe, currently measuring at billion light-years (space.com)
Assume a purely mathematical approach (the paper stacks perfectly in a line from the Earth to the Moon and nothing breaks its structure).
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Solution? What solution? The answer to everything is 4 2 .
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Buuut for those too lazy to make their own solution, let's dive:
Let the thickness of paper be X .
Then, generally, the number of folds will be as follows:
X ⋅ 2 F = D ,
where F is the number of folds and D is the distance to be folded over. (because if we take an object of thickness X , the distance D covered by the folds will double per fold F .)
For our problem,
X ⋅ 2 1 0 3 = 2 1 0 3 9 2 , 0 0 0 , 0 0 0 , 0 0 0 ⋅ 3 0 0 , 0 0 0 ⋅ 3 6 0 0 ⋅ 2 4 ⋅ 3 6 5 k m ⋅ 1 , 0 0 0 ⋅ 1 , 0 0 0
(1000*1000 for km to meters to millimeters).
Some Wolfing Around
reveals that the thickness of the paper should be approx. 0 . 0 8 5 8 millimeters.
So now we need to find how many folds to the Moon from Earth. Easy peasy:
0 . 0 8 5 8 m m ⋅ 2 F = 3 8 4 , 4 0 0 , 0 0 0 , 0 0 0 m m
Some Wolfing Around
will reveal, that F = 4 2 . (I'm sure we could... jump to the Moon for the other 0.02 folds. Or be pulled by it. Yeah. Be pulled by it :))