Huge Power Of 2

It can b written as 2^19999(2 - 1) = 2^x Then solve and compare both sides...

2^20000-2^19999 = 2^19999 (2-1) = 2^19999 so x = 19999

It can b written as 2^19999(2 - 1) = 2^x Then solve and compare both sides.

$2^{20000} - 2^{19999} = 2^{19999}\left(2 - 1\right) = 2^{19999} × 1$ . So, $x = \color{#69047E}{\boxed{19999}}$ .

[2^(19999+1)-2^19999]=2^x

or,2^19999(2-1)=2^x

or,2^19999=2^x

so,x=19999

for example.. 2^2 - 2^1 = 2^1
2^3 - 2^2 = 2^2
therefore 2^20000 - 2^19999 = 2^19999 by using the pattern established..

Hello pals,

as 2^(20 000) - 2^(19 999) = 2^x,

2 x 2^(19 999) - 2^(19 999) = 2^x,

2^(19 999) x( 2 - 1) = 2^x

2^x = 2^(19 999)

x=19 999, therefore x=19 999,

thanks...

2^20000-2^19999=2^x let the power 20000 is 'y',and as following 20000-19999=1 the power 19999 can be written as 'y-1', 2^y-2^y-1=2^x or 2^y-2^y 2^-1=2^x now taking common 2^y(1-2^-1)=2^x or 2^y(1-1/2)=2^x =>2^y(1/2)=2^x =>2^y/2=2^x now put the value of 'y', 2^20000/2=2^x or 2^20000 2^-1=2^x on L.H.S bases are same, 2^20000-1=2^x 2^19999=2^x on L.H.S & R.H.S bases are same therefore also their power can be write as equal x=19999

2^20000-2^19990 can be written as 2^19999(2-1) 2^19999(2-1) = 2^19999 and on comparison with RHS of the given equation, X value will be 19999.

2^20000-2^19999=2^19999

check by lowest value....no formula applied

2^20000-2^19999 = 2^19999(2-1) =2^19999 : Hence x=19999

Let $A = 2^{20000}$

So the equation can be $A-\frac{A}{2} = 2^x$

$=\frac{A}{2}$

$\frac{A}{2}$ is $\frac{2^{20000}}{2}$

So $20000-1=\boxed{19999}$

multiply and divide 2^19999 with 2 and take 2^20000 common so we get finally 2^19999 and now compare 2^x with 2^19999 so you get x value as 19999

{ 2 }^{ n }-2^{ n-1 }={ 2 }^{ n-1 }(2-1)