Which one is greater?
1 0 0 0 1 0 0 1 OR 1 0 0 1 1 0 0 0
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1 0 0 0 1 0 0 1 > 1 0 0 1 1 0 0 0 ⟺ 1 0 0 0 1 / 1 0 0 0 > 1 0 0 1 1 / 1 0 0 1 , which is true, since
x 1 / x is strictly decreasing in ( e , + ∞ ) , since
( x 1 / x ) ′ = − x 1 / x − 2 ( lo g ( x ) − 1 ) < 0 for x > e .
1 0 0 0 1 0 0 1 has 3004 digits, you forgot to add one in the characteristic of l o g ( 1 0 0 0 1 0 0 1 )
how do you find the no. of digits for 1001^1000
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number of digits = ⌊ lo g n ⌋ + 1 where n is a positive integer.
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but how do we find log 1001 without log tables
You are all wrong
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1000^1001 has 3003 digits.
1001^1000 has 3001 digits.
Thus 1000^1001 is greater.