humpty dumpty had a gr8 fall

Computer Science Level 2

A drunkard is walking along a straight road.He takes 5 steps forward and 3 steps backward,followed by 5 steps forward and three steps backward an so on.Each step is one meter long and takes 1 second.there is a pit on the road 11 meter away from the starting point.

How many seconds will it take the drunkard to fall into the pit?


The answer is 29.

Akansha Andhare by Akansha Andhare , 22, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Ashish Virani
Jul 12, 2014

Take 3 times 5 forward and 3 backward steps. So it will take 24 seconds and reach at 6 meters. Then 5 steps , So he will reach at 11 meters and total time will be 29 seconds.

3 Helpful 0 Interesting 0 Brilliant 0 Confused

good question

NARENDER PALUGULA - 6 years, 10 months ago
Noel Lo
Jul 15, 2015

Just before he falls into the pit will he be walking 5 metres ahead so before that, he would have covered a displacement of 11 − 5 = 6 11-5=6 metres. Now each round moves him forward by 5 − 3 = 2 5-3 = 2 metres, so to cover a displacement of 6 metres, he needs to cover 6 ÷ 2 = 3 6\div 2 = 3 rounds. Each round takes 5 + 3 = 8 5+3 = 8 seconds so 3 rounds would take 8 × 3 = 24 8 \times 3=24 seconds. This together with the 5 seconds needed for the last 5 steps forward gives us 24 + 5 = 29 24+5 = \boxed{29} seconds.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...