Hundreds Of Thousands Of Permutations
Probability
Level
1
If I use all the 9 digits to form a 9-digit integer, is it more likely that the resultant number is an odd number or an even number?
It is more likely to be an odd number
It is more likely to be an even number
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1 solution
An odd number can be defined as any integer that is not divisible by 2 .
From the divisibility rule of 2 , we know that,
Any number whose last digit is divisible by 2 is also divisible by 2 and is an even number
From this information, we can derive the following:
Any number whose last digit is not divisible by 2 is an odd number
The permutations really do not matter. From the set { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 } there are more odd numbers (i.e., { 1 , 3 , 5 , 7 , 9 } than there are even numbers (i.e., { 2 , 4 , 6 , 8 } ). So the answer is It is more likely to be an odd number
Correct me if my method is wrong but I know my answer is correct.