Hydraulic System

Pascal's Principle states that pressure is transmitted undiminished in an enclosed static fluid. That is, considering that the fluid is incompressible. Thus, we have:

$P_1 = P_2$

$\dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}$

$\dfrac{F_1}{F_2} = \dfrac{A_1}{A_2} = \dfrac{A_1}{10\cdot{A_1}}$

Therefore:

$\dfrac{F_1}{F_2} = \boxed{\dfrac{1}{10}}$

Just apply Pascal's Law of undiminished pressure according to which if pressure is applied to one part of a fluid, it is transmitted equally and undiminished to all parts of the fluid P1=P2 F1/A1=F2/A2 => F1/F2=A1/A2 =>F1/F2=1/10

p1=f1/a1

p2=f2/a1(10)

p1/p2=f1/a1/f2/a1(10)

p1/p2=f1/f2=1/10

f1/f2=1/10 or 1:10

in the hydrolic press (f1/f2)=(a1/a2) and according to the question 10a1=a2 so (f1/f2)=(a1/10a1) so (f1/f2 )= 1/10

F1 x A1 = F2 x A2 at the same level of the fluid as derived from Pascal's Pressure distribution law. Hence, the ratio of force will be inverse of the ratio of Areas.