A series of lines in the spectrum of atomic Hydrogen lies at wavelength range 656.46 nano meters ........... 410.29 nano meters (these are the two extreme values).What will be the wavelength of the next line in the series? Give your answer in nano meters.
Given : Rydberg Constant is
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The visible spectrum lies in the range 4 × 1 0 − 7 meters to 7 . 5 × 1 0 − 7 meters.The given wavelengths fall in this range and hence are visible.Therefore this ranger fall in the Balmer Series (the only visible series).Therefore we get n1=2 and for the wavelength 410.29 nano meter n2=6.(Where transition of electron is from n1 to n2).Therefore the wavelength corresponds to transition from n1=2 to n2=7.Solving we get the wavelength of the next line is 397 nano meters.