The pressure of a gas of volume 22.4 L is 3 atm at certain temperature.Then find the pressure of the gas of volume 44.8 L at the same temperature.
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Here we use the Ideal Gas Equation →
P V = n R T
Now since no. of moles n , temperature of the gas T and the universal gas constant, R are all constants, hence our equation reduces to →
P V = c o n s t a n t
Therefore as per the problem, when the volume is doubled , the pressure needs to be halved . Hence the answer is 1 . 5 a t m