Hyperbolic line!

Calculus Level 5

as the GIF above the stick might be considered as a line fastened on the disk circumference .

the disk radius is 1meter length.

u is the directing vector of the line .

r,t are the radius, circle tangent directing vectors.

the resulting shape formula using the disk center as reference of the coordinates...

c ( y y 0 ) 2 a 2 + ( x x 0 ) 2 b 2 = 1 c\frac{(y-y_0 )^2}{a^2} +\frac{(x-x_0)^2}{b^2} =1

what is 10 ( ( a b ) 2 c + 2 y 0 x 0 ) 10((ab)^2 -c+\sqrt{2}y_0-x_0) ?


The answer is 40.

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