Hyperloop: Air can be unpleasant

The Hyperloop is a hypothetical new fast transport system between cities, which works by launching pods that carry people through a very low air pressure tunnel. The normal pressure in the tunnel is 99 Pa 99~\mbox{Pa} , which is very low compared to the usual atmospheric pressure of 101 , 325 Pa 101,325~\mbox{Pa} . Since the pressure is so low the Hyperloop tunnel must be well sealed to prevent outside air from rushing in. A sudden increase in air pressure in a section of the tunnel can be rather unpleasant for the passengers in the pod.

Consider for example a hole being created in the Hyperloop tunnel, which leads to a sudden increase in the local air pressure from 99 Pa 99~\mbox{Pa} to 101 , 325 Pa 101,325~\mbox{Pa} while maintaining constant temperature and volume. If the normal drag force on the Hyperloop is 320 N 320~\mbox{N} , how much acceleration in g 's would the passengers in the Hyperloop experience if the pod hit the region of high pressure?

  • The mass of the pod is approximately 15000 kg 15000~\mbox{kg} .
  • g = 9.8 m/s 2 g=9.8~\mbox{m/s}^2


The answer is 2.228.

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1 solution

Gediminas Sadzius
Nov 26, 2020

From here one can see that drag force is directly proportional to the density of the surrounding media (air), and the density is proportional to pressure when the rest is kept constant. Upon a sudden increase in pressure, the pod will have to work against an increased drag force and will decelerate to a lower velocity corresponding to the new drag force. The new drag force will be 101325 Pa / 99 Pa = 1023.5 times higher, so the force balance is:

m × \times a = 1023.5 × \times Fd - Fd

where,

Fd - drag force, 320N

m - mass of the pod, 15000kg

a - deceleration of the pod, m/ s 2 s^{2}

The deceleration in terms of "g" is:

a = 1023.5 × F d F d g × m \frac{1023.5 \times\ Fd - Fd}{g \times\ m}

After putting the numbers in, the answer is 2.23 \boxed{2.23}

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