Hyperloop: Suspension forces

HELLOW TO ALL . IN ORDER TO KEEP POD SUSPENDED IN THE AIR THE AIR MUST EXERT FORCE EQUAL AND OPPOSITE TO THE FORCE EXERTED BY POD . WE KNOW THAT WEIGHT IS THE FORCE EXERTED BY EVERY OBJECT ON THE EARTH AND HERE ACCLERATION IS THE ACCELERATION DUE TO GRAVITY . SO WE KNOW THE RELATION
F = $mass \times acceleration$
. * F = $3100 \times9 . 8$ * . WHICH WILL GIVE YOU $\boxed{30380}$ N AS YOUR ANSWER .

The force exerted down by the Hyperloop, by Newton's second law $F=ma )$ , is $(3100kg)(9.8m/s^2)=30380N$ . To keep it suspended, the upward force must equal the downward force, so $\boxed{30380N}$ must be exerted on the pod.

The force exerted by the air cushion must be equal to the gravitational force on the pod. Using the formula $F=ma,$ we have $F = (3100 \; \text{kg})(9.8 \; \text{m/s/s}) = \boxed{30380} \; \text{N}.$

f=ma where f=3100*9.8=30380

3100*9.8 = 30380. Answer : 30.38E+3

You just have to multiply 3100 kg to 9,8 => 30380 kg Because your weight its mass x gravity

Since the Hyperloop functions by suspending on a low pressure cushion of air. The pressure should exert a force greater than its mass since the gravitational pull of the earth should be considered.

F=ma is the formula used to get the force in Newtons(N)

Simply substitute the given figures then multiply. Thus,

F= (3100 kg)(9.8 m/s²) then, F= 30380 kg.m/s² or 30400 kg.m/s²

that's the final answer.

In order to keep the pod on a cushion of air, the force exerted must be $F=m \times g$ , which means $F=3100 \times 9.8=30380$

F=ma But Here a=g Therefore here F=mg m=3100kg g=9.8m/s F=3100*9.8=30380

force=mass * acceleration

mass=3100kg, acceleration=9.8 m/s^2

force=3100 * 9.8

force=30380

(3100kg)(9.8 m/s^2) = 30380N The minimum force to be exerted

F=mg

F = force, weight (N)

m = mass (3100kg)

g = acceleration of gravity (9.8 m/s^2)

F=3100kg(9.8m/s^2) =30380kgm/s^2 or =30380 Newton