"I am Back" says Integration Part 4

Calculus Level 5

I = 0 π / 2 log ( cos ( x ) ) log 2 ( sin ( x ) ) d x I=\displaystyle \int _{ 0 }^{ \pi /2 }{ \log(\cos(x))\ \log^ 2 (\sin(x)) \ \mathrm d x }

If 16 I 16I can be represented in the form of a π ζ ( b ) c π log d ( f ) a\pi \zeta(b) - c\pi\log^d (f)

Find a + b + c + d + f a+b+c+d+f

Details and Assumptions

  • a , b , c , d , f a,b,c,d,f are positive integers not neccasarily distinct.

  • ζ \zeta denote the Riemann Zeta Function.

  • log \log is the natural logarithm.

  • f f is not a multiple of a perfect power of any integer greater than 1 1 .


The answer is 18.

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1 solution

Rajdeep Dhingra
Mar 17, 2015

The answer is :

2 π ζ ( 3 ) 8 π log 3 ( 2 ) \large 2\pi\zeta(3) - 8\pi\log^3 (2)

I will add the full solution as soon as I get some time. Till then, refer to this . This problem is entirely based on that problem with a few changes. @Ronak Agarwal has written a beautiful solution there.

Kartik Sharma - 6 years, 1 month ago

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