An algebra problem by kritarth lohomi

Algebra Level 2

Given that the sum of n terms of an series

S n = n 2 + n 1 S_n=n^2+n-1

Find the second term of the series


The answer is 4.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Sujoy Roy
Jan 7, 2015

n n th term of the given series is t n = S n S n 1 = n 2 + n 1 ( n 1 ) 2 ( n 1 ) + 1 = 2 n t_{n} = S_{n}-S_{n-1}=n^2+n-1-(n-1)^2-(n-1)+1=2n .

So, t 2 = 2 2 = 4 t_{2}=2*2=\boxed{4}

Vishal S
Jan 7, 2015

Second term= S 2 S_{2} - S 1 S_{1} =( 2 2 2^2 + 2 - 1) - ( 1 2 1^2 + 1 - 1)=5 - 1 = 4

Sakshi Taparia
Jan 7, 2015

for n=1, sum of the first term (or the first term itself)= 1^2 +1-1 =1

for n=2, sum of first 2 terms= 2^2 +2-1 =5

now, the first term is 1, so the second term is 5-1 =4

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...