I bet you can't make this one

Algebra Level 5

{ a ( x 4 + 1 ) = y + 1 x x 2 + y 2 = 1 \begin{cases} a(x^4+1)=y+1-|x| \\ x^2+y^2=1 \end{cases}

Find sums of all parameters a a such that the system of equations above have only one real solution.


The answer is 2.

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1 solution

Let assume that ( x 0 , y 0 ) (x_0, y_0) is solution of our system then one may see that ( x 0 , y 0 ) (-x_0, y_0) is also solution of our system.

It is cleared because we want only one solution that x 0 = 0 x_0=0 and y 0 = 1 , 1 y_0=-1,1

When you now solve the equation for a a you will easy get a = 0 , 2 a=0,2 . If you put back your solutions for a a you will see that for a = 0 a=0 there is indeed more solution. So the final answer is a = 2 a=2

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