Find the sum of all integral values of such that there exists positive integers , and satisfying
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Let us first consider the case when x 2 = y 2 = z 2
Hence, x = y = z
Then, 3 x 2 = k x 3
As x = 0 Therefore x 3 = k
∴ x = 1 , 3 ∴ k = 3 , 1
And we can easily prove by divisibility that there is no solution for x = y = z ∴ ∑ k = 1 + 3 = 4