I choose 15

( 15 0 ) + ( 15 1 ) + ( 15 2 ) + . . . . + ( 15 15 ) = ? {15 \choose 0}+{15 \choose 1}+{15 \choose 2}+....+{15 \choose 15}=?

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The answer is 32768.

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1 solution

Vaibhav Prasad
May 1, 2015

( n 0 ) + ( n 1 ) + ( n 2 ) + . . . . + ( n n ) = 2 n {n \choose 0}+{n \choose 1}+{n \choose 2}+....+{n \choose n}=2^n

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