I come bearing gifts!

Probability Level pending

Six people come to a party, each bearing five gifts. If each person gives one gift to each of the other five people, how many different ways can the entire set of 30 gifts be distributed at the party?


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The answer is 2985984000000.

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1 solution

Geoff Pilling
May 12, 2016

Each person can give their gifts out in 5 ! = 120 5! = 120 ways. Since their are six people, the total number of permutations is 12 0 6 = 2985984000000 120^6 = \boxed{2985984000000}

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