If grams of a metal gives grams of its oxide, the equivalent mass of the metal (in grams) is
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Here amount of metal in y gms of metallic oxide is x gms
So amount of oxygen in y gms of oxide is (y-x) gms
We know that equivalent weight of oxygen is 8
Now
(y-x) gms of oxygen react with x gms of metal
Therefore 8 gms of oxygen react with 8x/(y-x) gms of metal.
Therefore equivalent weight of metal is 8x/(y-x)