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Algebra Level 2

Evaluate ( 1 + 1 4 ) ( 1 + 1 5 ) ( 1 + 1 6 ) . . . ( 1 + 1 2014 ) ( 1 + 1 2015 ) \displaystyle\left(1+\frac{1}{4}\right) \left(1+\frac{1}{5}\right) \left(1+\frac{1}{6}\right) ... \left(1+\frac{1}{2014}\right) \left(1+\frac{1}{2015}\right)


The answer is 504.

Hobart Pao by Hobart Pao , 23, USA

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1 solution

Saad Mukarram
Mar 28, 2015

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