I didn't expect that coming

Calculus Level 5

[ d 2 d x 2 ( sin 1 ( 2 x 2 + 4 ) + cos ( 2 x 7 x 2 + 1 ) ) ] x = 2 \large{\left[ \frac { { d }^{ 2 } }{ d{ x }^{ 2 } } \left( \sin ^{ -1 }{ \left( 2{ x }^{ 2 }+4 \right) } +\cos { \left( \frac { 2x }{ 7{ x }^{ 2 }+1 } \right) } \right) \right] _{ x=\sqrt { 2 } }}

If the value of above given second derivative can be expressed as

A i B C D E sin ( E E F ) G H cos ( E E F ) J \large{\\ \frac { Ai }{ B\sqrt { C } } -\frac { D\sqrt { E } \sin { \left( \frac { E\sqrt { E } }{ F } \right) } }{ G } -\frac { H\cos { \left( \frac { E\sqrt { E } }{ F } \right) } }{ J } }

For integers A , B , C , D , E , F , G , H , J A,B,C,D,E,F,G,H,J and E , C E,C are square-free and i 2 = 1 i^{2}=-1 ,

Find A + B + C + D + E + F + G + H + J A+B+C+D+E+F+G+H+J

Note:-

gcd ( A , B ) = gcd ( D , F ) = gcd ( E , F ) = gcd ( H , J ) = 1 \gcd{(A,B)}=\gcd{(D,F)}=\gcd{(E,F)}=\gcd{(H,J)}=1


The answer is 55201.

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